What is the free energy change in reaction to 461 kelvin quilojoules is a change in enthalpy and entropy change of -58 -93 quilojoules. 3 joules per kelvin?

One Response to “What is the free energy change in kilojoules of a reaction at 461 kelvin whose enthalpy change is -58 kilojoul”
  1. Johnny D says:

    Delta G=Delta H- T x Delta S

    T x Delta S=461 K x -93.3 j/K x 1 Kj/1000 j=-43.0 Kj

    Delta H-T x Delta S=-58.0 Kj-(-43.0 Kj)=-15.0 Kj

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